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(F)=12F^2+2
We move all terms to the left:
(F)-(12F^2+2)=0
We get rid of parentheses
-12F^2+F-2=0
a = -12; b = 1; c = -2;
Δ = b2-4ac
Δ = 12-4·(-12)·(-2)
Δ = -95
Delta is less than zero, so there is no solution for the equation
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